>In vernacular the solid cone is a teepee: D is >its base; A is its peak; C is the fire in the >center of the base; the axis is the smoke rising; >and theta is the angle between the smoke rising >and one of the support poles from the edge of the >base to the peak. > >NASA gives you the coordinates of a mosquito M and >you are asked to calculate (using FB on your ibook) >whether the mosquito is inside the teepee. You >already know the coordinates of A and C and the >value of the angle theta, 0 < theta < pi/2 > >Three things are easily calculated and will give the >solution. > > (i) the distance AM, call it |AM| > (ii) the distance AC, , call it |AC| > (iii) tha angle (CAM), call it phi ( 0<= phi <= pi ) > >Indeed the mosquito M is in the teepee precisely >if > >(a) |AM|*COS(phi) is greater than 0 and less than |AC| >(b) phi < theta > >You all know how to evaluate the distances. >The vector inner product <AM,AC> determines >phi by the equation:- > > <AM,AC> = |AM|*|AC|*COS(phi) > >Here <AM,AC> is: > > <AM,AC> = AM1*AC1 + AM2*AC2 + AM3*AC3 > > where > > AM = (AM1,AM2,AM3) = (A1-M1,A2-M2,A3-M3) > AC = (AC1,AC2,AC3) = (A1-C1,A2-C2,A3-C3) > >Recall that |AM|=SQR(<AM,AM>), |AC|=SQR(<AC,AC>). > >That's a solution with a minimum of sweat. And no >special coordinate transformations are needed! > >Cheers > >Laurent S. Laurent, Have I translated this into code correctly? (sX#,sY#,sZ#) is the coordinate of the peak (A), (lX#,lY#,lZ#) is the coordinate of the mosquito (M) and the center (C) is the origin (0,0,0). Looking at your suggestions and applying what I think are the correct equations I get the following code. '-----Begin FB^3 Code----- 'This should format properly in the FB Editor SLX# = lX#-sX# : SLY# = lY#-sY# : SLZ# = lZ#-sZ# SL# = sqr(SLX#^2 + SLY#^2 +SLZ#^2) SC# = sqr(sX#^2 + sY#^2 + sZ#^2) SLSC# = SLX#*sX# + SLY#*sY# + SLZ#*sZ# phi# = acos(SLSC#/(SL#*SC#) SLcosphi# = SL# * cos(phi#) long if SLcosphi# > 0 and SLcosphi# <= SC# and phi# <= theta# inCone = _zTrue xelse inCone = _false end if '----- End FB^3 Code ----- Thanks for the help so far, Regards, Ashley ~)~ ============================================================= Ashley Butterworth Email: macbse@... ============================================================= _________________________________________________________ Do You Yahoo!? Get your free @yahoo.com address at http://mail.yahoo.com